• laserm@lemmy.world
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    8 hours ago

    Why would a mathematician use j for imaginary numbers and why would engineer be mad at them?

    • CyanideShotInjection@lemmy.world
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      7 hours ago

      The only thing I can think of is that the OP studied electrical engineering at some point. But it’s a 4chan story so probably fake anyway.

    • dustycups@aussie.zone
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      7 hours ago

      I think it might be the wrong way around: Engineers like to use j for imaginary numbers because i is needed for current.

    • ThePuy@feddit.nl
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      7 hours ago

      Mathematicians are taught to be elastic with notation, because they tend to be taught many different interpretations of the same theory.

      On the other hand engineers use more strict and consistent notation, their classes have a more practical approach.

      Using the same notation makes it faster to read and apply math, a more agile approach helps with learning new theories and approaches and with being creative.

    • jyl@sopuli.xyz
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      6 hours ago

      Wtf mate, nothing that serious. Anon teased him and the score was settled when they did the thing later that night.

      The story looks pretty fake and gay anyway, but it’s more wholesome than your idea.

    • Neverclear@lemmy.dbzer0.com
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      7 hours ago

      hate fuck:

      An act of aggressive sex with someone as if they had no respect for the person as an equal human being, regardless if they actually do, or not. Hate fucking usually entails aggressive, sometimes violent, degrading, and humiliating sexual acts and behaviors perpetrated by an aggressive party onto a submissive, solely in the interest of the aggressor’s own pleasure and amusement, and without regard for the submissive party’s enjoyment or well being.

      Unlike rape, hate fucking is a form of consensual sex where the submissive party has agreed (for whatever reason) to accept the treatment and behavior of the aggressor.

      Though unlike proper BDSM, the submissive party has not previously discussed boundaries, likes or dislikes, and doesn’t necessarily enjoy all, or even any of the treatment they receive.

      https://www.urbandictionary.com/define.php?term=hate+fuck

  • iAvicenna@lemmy.world
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    20 hours ago

    operative?

    Also mathematicians use i for imaginary, engineers use j. The story does not add up. I have never seen a single mathematician use j for imaginary.

    • Unlearned9545@lemmy.world
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      12 hours ago

      Engineer here: mostly use i, but have seen j used plenty. First time I saw j used was by a maths professor.

      • iAvicenna@lemmy.world
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        12 hours ago

        Interesting I never saw j from a maths person. Friends (from a decade ago!) in electronics eng dep said they use j because i was reserved for current. perhaps the latter depends on the department.

        • Chakravanti@monero.town
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          8 hours ago

          j is pretention when a math doer does it. j is for engineers and you don’t even understand the bubble ratio filtering equation let alone be asking to envision what temp you did the mAEth in.

          You got lost in the number of letters instead of realizing the MeTowel’s important presence til that EOTU moment of that manufa turing of Big Black Goles you get to watch it all happen again as Thanos facepalms.

    • sartalon@lemmy.world
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      19 hours ago

      As an EE, I used both. Def not a mathematician though. Fuck that, I just plug variables into programs now.

    • BlackRoseAmongThorns@slrpnk.net
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      11 hours ago

      Integrals are an expression that basically has an opening symbol, and an operation that is written at the end of it that is used also as a closing symbol, looks kinda like:$ {some function of x} dx.

      The person basically said “the dx part can be written at the start also, and that would make my so mad :3”: $ dx {some function of x}.

      This gets their so mad because understandably this makes the notation non-standard and harder to read, also you’d have to use parentheses if the expression doesn’t just end at the function.

      Note: dollar used instead of integral symbol

    • int_not_found@feddit.org
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      9 hours ago

      An integral is usually written like ∫ f(x) dx or alternatively as df(x)/dx. Please note that this is just a way to apply the operation ‘Integration’, like + applies the operation ‘Addition’. There is no real multiplication or division.

      But sometimes you can take a shortcut and treat dx as a multiplied constant. This is technically not correct, but under the right circumstances lands you at the same solution as the proper way. This then looks like this ∫ f(y) dy/dx dx = ∫ f(y) dy

      Another thing you can do is to move multiplicative constants from inside the Integral to in front of the Integral: ∫ 2f(x) dx = 2 ∫ f(x) dx. (That is always correct btw)

      What anon did was combine those two things and basically write ∫ f(x) dx = dx ∫ f(x). Which is nonsensical, but given the above rules not easily disproven.

      This is more or less the same tactic used by internet trolls just in a mathy way. Purposefully misinterpreting arguments and information, that cost the other party considerably more energy to discover and rebut. Hence the hate fuck.

  • Zagorath@aussie.zone
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    1 day ago

    Fake and gay.

    No way the engineer corrects the mathematician for using j instead of i.

    • TheSlad@sh.itjust.works
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      23 hours ago

      Right? They got that shit backwards. Op is a fraud. i is used in pure math, j is used in engineering.

      • Chakravanti@monero.town
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        8 hours ago

        That’s hilarious. You’re not seeing what’s going on backwards just like that (as I point at the point going nowhere shitty) in an equation that is finding as many clAEver ways to say something you actually not caring about talking about.

        That’s like, "How many time van express the only thing that van’t be done until the 'verse itself tries to do what can’t be done and sever your…

        …Oh, I see…you don’t have ([of course, because you can’t have to give {is}) nothing)] to give.

        Unable to sea time doesn’t mean we can’t see(k)ER the mAETh.ac(k).cc(k).08

        The only thin(g):(k) that doesn’t ever be never, is not at alla hack(g)in(g).G your lackthereof to divi…

    • LeFrog@discuss.tchncs.de
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      1 day ago

      As an engineer I fully agree. Engineers¹ aren’t even able to do basic arithmetics. I even cannot count to 10.

      ¹ Except maybe Electrical engineers. They seem to be quite smart.

    • Kogasa@programming.dev
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      1 day ago

      The mathematician also used “operative” instead of, uh, something else, and “associative” instead of “commutative”

      • Zagorath@aussie.zone
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        16 hours ago

        “operative” instead of, uh, something else

        I think they meant “operand”. As in, in the way dy/dx can sometimes be treated as a fraction and dx treated as a value.

          • Zagorath@aussie.zone
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            12 hours ago

            The operand is the target of an operator

            Correct. Thus, dx is an operand. It’s a thing by which you multiply the rest of the equation (or, in the case of dy/dx, by which you divide the dy).

              • Zagorath@aussie.zone
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                11 hours ago

                You’re misunderstanding the post. Yes, the reality of maths is that the integral is an operator. But the post talks about how “dx can be treated as an [operand]”. And this is true, in many (but not all) circumstances.

                ∫(dy/dx)dx = ∫dy = y

                Or the chain rule:

                (dz/dy)(dy/dx) = dz/dx

                In both of these cases, dx or dy behave like operands, since we can “cancel” them through division. This isn’t rigorous maths, but it’s a frequently-useful shorthand.

                • Chrobin@discuss.tchncs.de
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                  8 hours ago

                  I do understand it differently, but I don’t think I misunderstood. I think what they meant is the physicist notation I’m (as a physicist) all too familiar with:

                  ∫ f(x) dx = ∫ dx f(x)

                  In this case, because f(x) is the operand and ∫ dx the operator, it’s still uniquely defined.

    • bitcrafter@programming.dev
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      18 hours ago

      Imagining your death. :P

      But seriously, it’s perfectly sensible when remember that i is just the mathematical representation of “left turn”, just like -1 is the mathematical representation of “go backwards”-- and as we know, two left turns sends you backwards. So think about this triangle in the following way:

      Imagine you are a snail, starting at the origin. Now imagine that you walk forward 1 step along the horizontal line. Then you turn 90° to the left to start walking along the vertical line, but then, because you need to walk i steps along this line you take another 90° turn to the left, which means that you are now walking backwards and you end up back at the origin. How far away from the origin are you? Zero steps.

    • burntbacon@discuss.tchncs.de
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      6 hours ago

      Thado-mathocist. The real chad all along.

      It makes me wonder if somewhere out there in a multiverse, a community of lisping incels all collectively draw the chad wojak as as an aramaic looking dude.

  • Phoenix3875@lemmy.world
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    24 hours ago

    I think rather d/dx is the operator. You apply it to an expression to bind free occurrences of x in that expression. For example, dx²/dx is best understood as d/dx (x²). The notation would be clear if you implement calculus in a program.

    • yetAnotherUser@discuss.tchncs.de
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      9 hours ago

      I just think of the definition of a derivative.

      d is just an infinitesimally small delta. So dy/dx is literally just lim (∆ -> 0) ∆y/∆x. which is the same as lim (x_1 -> x_0) [f(x_0) - f(x_1)] / [x_0 - x_1].

      Note: -> 0 isn’t standard notation. But writing x -> 0 requires another step of thinking: y = f(x) therefore ∆y = ∆f(x) = f(x + ∆x) - f(x) so you only need x approaching zero. But I prefer thinking d = lim (∆ -> 0) ∆.

      • ඞmir@lemmy.ml
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        19 hours ago

        If you use exterior calculus notation, with d = exterior derivative, everything makes so much more sense

  • vivalapivo@lemmy.today
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    1 day ago

    As a physicist I can’t understand why would anyone complain about a +jb or $\int dx f(x)$. Probably because we don’t fuck